Sistem pengalamatan jaringan
Mencari Network dan Broadcast
Soal:
a.
192.168.1.100/24
b.
172.71.17.17/29
c.
202.125.100.200/26
d.
10.10.10.10/30
e.
191.168.100.160/27
f.
220.200.20.30/28
g.
180.60.50.150/25
Jawab:
a.
192.168 .1.100/24
llllllll.llllllll.llllllll.00000000
Subnet mask :
255.255.255.0
Network :
192.168.1.0
Broadcast :
192.168.1.255
NB:karena
slash 24 sudah pas maka dari itu tidak perlu dihitung dan bisa di nalar.
b.
172.71.17.17/29
llllllll.llllllll.llllllll.lllll000
Subnet mask :
255.255.255.248
Network :
2x = 25 = 32
Host :2y = 23 – 2 = 8 – 2 = 6
Kelipatan :
256 – 248 = 8
( 0,8,16,24,32,40,48,56,64,72,80 ……)
Netwok
|
172.71.17.16
|
172.71.17.32
|
Ip Awal
|
172.71.17.17
|
172.71.17.33
|
Ip akhir
|
172.71.17.30
|
172.71.17.38
|
Broadcast
|
172.71.17.31
|
172.71.17.39
|
c.
202.125.100.200/26
llllllll.llllllll.llllllll.ll000000
Subnet mask :
255.255.255.192
Network :
2x = 22 = 4
Host :
2y - 2 = 26 – 2 =
64 – 2 = 62
Kelipatan :
256 – 192 = 64
(0,64,128,192,256)
Network
|
202.125.100.128
|
202.125.100.192
|
Ip awal
|
202.125.100.129
|
202.125.100.193
|
Ip akhir
|
202.125.100.190
|
202.125.100.254
|
broadcast
|
202.125.100.191
|
202.125.100.255
|
d.
10.10.10.10/30
llllllll.llllllll.llllllll.llllll00
Subnet mask :
255.255.255.252
Network :
2x = 26 = 64
Host :
2y – 2 = 22 – 2 = 4-2 =2
Kelipatan :
256 – 252 = 4
(0,4,8,12,16,20,24,28,32,36,40,…)
Network
|
10.10.10.8
|
10.10.10.12
|
Ip awal
|
10.10.10.9
|
10.10.10.13
|
Ip akhir
|
10.10.10.10
|
10.10.10.14
|
Broadcast
|
10.10.10.11
|
10.10.10.15
|
e.
191.168.100.160/27
llllllll.llllllll.llllllll.lll00000
subnet mask :
255.255.255.224
Network :
2x = 23 = 8
Host :2y-2=
25 – 2 = 32 – 2 = 30
Kelipatan :
256 – 224 = 32
(0,32,64,96,128,160,192,…)
Network
|
191.168.100.160
|
191.168.100.192
|
Ip awal
|
191.168.100.161
|
191.168.100.193
|
Ip akhir
|
191.168.100.190
|
191.168.100.222
|
Broadcast
|
191.168.100.191
|
191.168.100.223
|
f.
220.200.20.30/28
llllllll.llllllll.llllllll.llll0000
Subnet mask :
255.255.255.240
Network :
2x = 24 = 16
Host :
2y – 2 = 24 – 2 = 16 – 2 = 14
Kelipatan :
256 – 255 = 16
(0,16,32,48,64,80,96, …)
Network
|
220.200.20.16
|
220.200.20.32
|
Ip awal
|
220.200.20.17
|
220.200.20.33
|
Ip akhir
|
220.200.20.30
|
220.200.20.46
|
Broadcast
|
220.200.20.31
|
220.200.20.47
|
g.
180.60.50.150/25
llllllll.llllllll.llllllll.l0000000
subnet mask :
255.255.255.128
Network :2x
= 21 = 2
Host :2y
– 2 = 27 – 2 = 128 – 2 = 126
Kelipatan :
256 – 128 = 128
(0,128,256)
Network
|
180.60.50.0
|
180.60.50.128
|
Ip awal
|
180.60.50.1
|
180.60.50.129
|
Ip akhir
|
180.60.50.126
|
180.60.50.254
|
Broadcast
|
180.60.50.127
|
180.60.50.255
|
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